What Are The Consequences Of Violating A Victim Protective Order In Oklahoma?

It is a crime to violate a Victim Protective Order. This is covered in 22 O.S. § 60.6. The first violation is a misdemeanor. Punishment consists of a fine of up to $1,000 and/or up to one year in the county jail. A second offense is a felony. This carries from one to three years in the Department of Corrections and a fine of $2,000 –$10,000.

Violation Of Victim Protective Order That Causes Physical Injury Or Physical Impairment

Victim Protective OrderA Victim Protective Order violation resulting in physical injury or physical impairment to the plaintiff or any person mentioned in a protective order is a misdemeanor. The violator can spend 20 days–1 year in jail. The maximum fine is $5,000.

The second or subsequent violation of a protective order that causes physical injury or physical impairment to a plaintiff or any other person named in the protective order is a felony. This carries a penalty of one to five years in the Department of Corrections and a fine ranging from $3,000–$10,000. The defendant also must undergo or participate in a counseling service as necessary to bring about the cessation of domestic abuse, stalking, or harassment.

Source:

22 O.S. § 60.6

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